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The Ruler
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Default Official Riddles Thread - 04-12-2005



i hope every one will enjoy these riddles
They are not really mine but some of them are
i got looooads so i thought i will start a thread of riddles.
Now lets see...........where shall i start.........

lets start with one of my riddles.......
Once me and my dad was on our way to school in Kuwait.
He asked me that........

I have some apples in my right hand and some in the left hand. Now, if I minus an apple from my left hand and add it to my right hand, then both of my hands has equal no. of apples. And if I minus an apple from my right hand and add it to my left hand, then my left hand contains double the no. of apples as in my right hand.
How many apples do I have in each of the hands?

i was verrrrry confused. i went to school and asked my friends but none of them knew the answer. i asked everyone i knew but none of them could get it.
but then i came home and asked him for the answer and he told me.........Well i was very small at that time anyway

So give this riddle some tries and i will be back with another brainteasing one insha'allah. But my first 21 riddles are going to be on Maths .


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Default Re: Tagrid's riddles thread! - 04-12-2005



come on guys........
i have been waiting for ages.........no reply.........
if you think you cant do it, doesnt matter jus give it a try;)

i am sure you will get it insha'allah


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Default Re: Tagrid's riddles thread! - 04-12-2005

erm......
   
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Default Re: Tagrid's riddles thread! - 04-12-2005

isnt it
1
   
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WomanOfJihad
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Default Re: Tagrid's riddles thread! - 04-12-2005



errr WILD GUESS

u cant hold 2 apples in one hand ..

its ONE Apple on each hand?

(ALAHU Alim)

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Default Re: Tagrid's riddles thread! - 04-12-2005

Quote:
Originally Posted by WomanOfJihad


errr WILD GUESS

u cant hold 2 apples in one hand ..

its ONE Apple on each hand?

(ALAHU Alim)

Subhanallah.....i made a great mistake . forgive me for that. its meant to be some apples on one side and some on the other side.
it was long ago you see and i almost forgot i was 9 at that time....almost 6 years ago.
Sorry

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Default Re: Tagrid's riddles thread! - 04-12-2005

Quote:
Originally Posted by niqaabii
isnt it
1
umm...good guess,but..........nope ;)

OK now here comes the next one.........

The ages of a father and son add up to 66. The father's age is the son's age reversed.
How old could they be? (3 possible solutions).


this one should be abit easier for the ones who are good in maths......so give it a try...i am sure there are lots of ppl in this forum who are xtremely good at maths..........;)

when i reach the 5th riddle i will probably answer the first question if no one gets the answer to it.......


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Ansar Al-'Adl
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Default Re: Tagrid's riddles thread! - 04-12-2005

Quote:
Originally Posted by Tagrid
I have some apples in my right hand and some in the left hand. Now, if I minus an apple from my left hand and add it to my right hand, then both of my hands has equal no. of apples. And if I minus an apple from my right hand and add it to my left hand, then my left hand contains double the no. of apples as in my right hand.
Good one.
Simple algebra.

Let R rep. apples in right hand, L rep. apples in left hand.
Quote:
if I minus an apple from my left hand and add it to my right hand, then both of my hands has equal no. of apples
L-1=R+1
L=R+2

(the left hand has two more apples than the right hand)

Quote:
And if I minus an apple from my right hand and add it to my left hand, then my left hand contains double the no. of apples as in my right hand.
2(R-1)=L+1
Since L=R+2, then...
2(R-1)=(R+2)+1
2R-2=R+3
2R=R+5
R=5
IF R=5 and L=R+2, then L=(5)+2=7


There are seven apples in the left and five apples in the right.


That was from ages ago. Hope everyone enjoyed the simple math lesson. ;)

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Default Re: Tagrid's riddles thread! - 04-13-2005

Quote:
Originally Posted by Ansar Al-'Adl
Good one.
Simple algebra.

Let R rep. apples in right hand, L rep. apples in left hand.

L-1=R+1
L=R+2
(the left hand has two more apples than the right hand)



2(R-1)=L+1
Since L=R+2, then...
2(R-1)=(R+2)+1
2R-2=R+3
2R=R+5
R=5
IF R=5 and L=R+2, then L=(5)+2=7


There are seven apples in the left and five apples in the right.


That was from ages ago. Hope everyone enjoyed the simple math lesson. ;)



thats CORRECT!!!
try the next one and im sure it'll be correct


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Ansar Al-'Adl
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Default Re: Tagrid's riddles thread! - 04-15-2005

you have some really good riddles Tagrid.
Quote:
Originally Posted by Tagrid
The ages of a father and son add up to 66. The father's age is the son's age reversed.
How old could they be? (3 possible solutions).
hmmm.. interesting. I was waiting to see if someone else would give it a try, but I guess I'll give this one a shot as well.

By "reversed" I assume you mean that is the father's age is 56, then the son's age is 65?

Okay, let's take a look at the question then. We will just set up some matrices.

The age's must be two digit numbers since they add up to 66.

If the father's age is represented by [x y], then the son's age is represented by [y x]. From the question, we know that:
[x y] + [y x] = [6 6]

Therefore, any value that satisfies the equation x+y=6, is an acceptable digit of the ages. Possible substituions include:
1+5=6, 2+4=6, 3+3=6

Therefore, the possible ages of the father and the son (respectively) are:
51 and 15
24 and 42

the last one (33 and 33) is inadmissable because the father and the son cannot be of the same age.

Is this correct?
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Default Re: Tagrid's riddles thread! - 04-16-2005

Quote:
Originally Posted by Ansar Al-'Adl
you have some really good riddles Tagrid.

hmmm.. interesting. I was waiting to see if someone else would give it a try, but I guess I'll give this one a shot as well.

By "reversed" I assume you mean that is the father's age is 56, then the son's age is 65?

Okay, let's take a look at the question then. We will just set up some matrices.

The age's must be two digit numbers since they add up to 66.

If the father's age is represented by [x y], then the son's age is represented by [y x]. From the question, we know that:
[x y] + [y x] = [6 6]

Therefore, any value that satisfies the equation x+y=6, is an acceptable digit of the ages. Possible substituions include:
1+5=6, 2+4=6, 3+3=6

Therefore, the possible ages of the father and the son (respectively) are:
51 and 15
24 and 42

the last one (33 and 33) is inadmissable because the father and the son cannot be of the same age.

Is this correct?


I first thought it was 33 but than remembered the father and son couldn't be the same age ..your really smart :brother:
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Default Re: Tagrid's riddles thread! - 04-16-2005

can't it be 06 n 60 ??? ;)
   
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Default Re: Tagrid's riddles thread! - 04-16-2005

JazakAllah khair for the kind words, Sis Mou'minah,

And I think you're right Br. zAk, that is also a possibility.
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Default Re: Tagrid's riddles thread! - 04-16-2005

next plz !
   
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Default Re: Tagrid's riddles thread! - 04-16-2005

I like these ones, esp those maths ones,


in the entrance exam for MCA[which i'm doing currently],
v had similar questions, abt 200, tht too to do them in just 150 Mins [2 & 1/2 hrs]
n i scored excellent marks

the entrance exam for BCA was also similar but there v had 2 hrs n 150 questions.
n there too i topped in my college

so..... let some gud ones flow in...
   
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