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Tahmina
06-13-2009, 01:10 PM
is anyone gd at quadratics
i hav my summer exams next next
i need help on this question
Make X the subject of the formula y= 3x+4 divide by x-3
ta:)
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GreyKode
06-13-2009, 01:23 PM
format_quote Originally Posted by
Tahmina
is anyone gd at quadratics
i hav my summer exams next next
i need help on this question
Make X the subject of the formula y= 3x+4 divide by x-3
ta:)
I can try to help out if you could only clarify the question.
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alcurad
06-13-2009, 01:29 PM
you mean as (x=) instead of (y=) then divide by (x-3) ?
I don't understand the last part, but here goes:
consider / as division, then:
y = 3x + 4
y - 4 = 3x + 4 - 4
(y - 4) / 3 = 3x / 3
(y - 4) / 3 = x
I hope that helped :)
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Tahmina
06-13-2009, 01:57 PM
yes it is
can you help
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~Raynn~
06-13-2009, 02:04 PM
^ Okey dokey, in which case...
y = (3x + 4)/(x - 3)
(x - 3)y = 3x + 4 .....[multiply both sides by x - 3]
xy - 3y = 3x + 4 .....[expand the brackets]
xy - 3x = 3y + 4 .....[bring all the x terms on one side]
x (y - 3) = 3y + 4 .....[take out a factor of x]
x = (3y + 4)/(y - 3) .....[divide both sides by y - 3]
Hope that helps!
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alcurad
06-13-2009, 02:04 PM
ah i see, then is it (3x-4)/(3-x) or just 3x-[4/(3-x)]?
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~Raynn~
06-13-2009, 02:17 PM
^ Nope, nope, that's exactly right! And if you take out a factor of -1 in both the top and bottom, and cancel them out, you get the same form...but it kinda looks nicer with less -ve signs, lol :D.
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~Raynn~
06-13-2009, 02:34 PM
:giggling: Terrrible...not that it makes any difference whatsoever, of course, lol...
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Tahmina
06-13-2009, 02:52 PM
thanks that helped
:happy:
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