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Re: The art of mesh analysis
the only thing i understand, is the drawing of the smiley face. Needs to comb hair and get plactic surgery on the nose , otherwise very pretty.
My heart, so precious,
I won't trade for a hundred thousand souls.
Your one smile takes it for free.Rumi
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Re: The art of mesh analysis
hey abdullahi, if it might interest you I am an electrical engineer. I think I can help u if you want.
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Re: The art of mesh analysis
format_quote Originally Posted by
GreyKode
hey abdullahi, if it might interest you I am an electrical engineer. I think I can help u if you want.
fantastic ! can you check if my mesh analysis is correct thanks
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Re: The art of mesh analysis
v12=R3(I2-I3) - R4(12-13)
I think something is wrong here
correction :
v12 = R3(I2-I3)+(I2-I1)R4
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Re: The art of mesh analysis
yes thanks thats right my mistake.....
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Re: The art of mesh analysis
loop1
v12 = R3(I2-I3)+(I2-I1)R4
loop2
0=I3*R2 + (I3-I1)*R1 + (I3-I2)*R3
loop3
I1=1A.
Now substituting you need to solve the following 2 eqns
12=6*(I2-I3) + 8*(I2-1)
0=4*I3 + (I3-1)*4 + (I3-I2)*6
20 = 14*I2 -6*I3
4 = 14*I3 - 6*I2
Last edited by GreyKode; 04-22-2009 at 11:39 PM .
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Re: The art of mesh analysis
format_quote Originally Posted by
GreyKode
loop1
Now substituting you need to solve the following 2 eqns
12=6*(I2-I3) - 8*(I2-I3)
0=4*I3 + (I3-1)*4 + (I3-I2)*6
which gives us this
v12 = 6(I2)-6(I3) - 8(12) - 8
0=4(I3) + 4(I3) - 4 + 6(I3) - 6(I2)
.
.
.
.
20 = 14 I2 - 6 I3
4 = - 6 I2 - 14 I2
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Re: The art of mesh analysis
I am afraid youre mistaken, maybe its my equations.
But check again.
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Re: The art of mesh analysis
12=6*(I2-I3) - 8*(I2-I3)
once you add the value this is what you get:
v12 = 6(I2)-6(I3) - 8(12) - 8
thats how i did it..i hope its clear because you cant really explain it in words
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Re: The art of mesh analysis
sorry..check my edited post
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Re: The art of mesh analysis
oh ok so how did you get 14 on the bottom line did you times 6 by 2.33333333333
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Re: The art of mesh analysis
starting from here
12=6*(I2-I3) + 8*(I2-1)
0=4*I3 + (I3-1)*4 + (I3-I2)*6
expanding brackets
12=6*I2-6*I3 + 8*I2 - 8 ----> 12+8 = 6*I2-6*I3 + 8*I2 ----> 20 = 14*I2 - 6I3
0=4*I3 + I3*4 - 4 + I3*6 - I2*6 ----> 4 = 4*I3 + I3*4 + I3*6 - I2*6 --->
4 = 14*I3-I2*6
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Re: The art of mesh analysis
starting from here
12=6*(I2-I3) + 8*(I2-1)
0=4*I3 + (I3-1)*4 + (I3-I2)*6
expanding brackets
12=6*I2-6*I3 + 8*I2 - 8 ----> 12+8 = 6*I2-6*I3 + 8*I2 ----> 20 = 14*I2 - 6I3
0=4*I3 + I3*4 - 4 + I3*6 - I2*6 ----> 4 = 4*I3 + I3*4 + I3*6 - I2*6 --->
4 = 14*I3-I2*6
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Re: The art of mesh analysis
ok now what about the simultaneous equation part..............
you have to change this
20 = 14*I2 -6*I3
4 = 14*I3 - 6*I2
to this
20 = 14 I2 - 6 I3
4 = - 6 I2 - 14 I2
and then finding I3 by multiplying the bottom line by 2.333333333
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Re: The art of mesh analysis
format_quote Originally Posted by
Abdullahii
ok now what about the simultaneous equation part..............
you have to change this
20 = 14*I2 -6*I3
4 = 14*I3 - 6*I2
to this
20 = 14 I2 - 6 I3
4 = - 6 I2 + 14 I3
and then finding I3 by multiplying the bottom line by 2.333333333
20 = 14 I2 - 6 I3
4 = - 6 I2 + 14 I3 * 14/6
20 = 14 * I2 - 6* I3
56/6 = -14 *I2 + 14*(14/6)* I3 adding
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Re: The art of mesh analysis
format_quote Originally Posted by
GreyKode
20 = 14 I2 - 6 I3
4 = - 6 I2 + 14 I3 * 14/6
20 = 14 * I2 - 6* I3
56/6 = -14 *I2 + 14*(14/6)* I3 adding
wow thats just confused me
this is what i did
20 = 14 I2 - 6 I3
4 = - 6 I2 + 14 I3<<<<<<<<<time by 2.333333333333
outcome is 9.3333333 = 14 + 32.666666666
then 20 = 14 I2 - 6 I3
9.3333333 = 14 + 32.666666666
---------------------------------------------
10.6 0 -26.7
10.7/26.7 = 0.4007 ampere
I3 = 0.4007 ampere
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Re: The art of mesh analysis
i had the test today inshallah ive done enough...you guyz just make dua for me
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Re: The art of mesh analysis
How was it? Anything challenging?
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Re: The art of mesh analysis
phasor diagrams, i have know clue ....i just guessed.....and opamp.... those two i dont really understand because i never went for lectures,i kinda slacked off
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