Mathematical problems...

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View attachment 3133

View attachment 3134



A flash chamber operating 80 degrees C and 500kPa is separating 1000 kg moles/hr of a feed that is 10 mole %ethane, 5 mole %propane, 15 % n-butane, 10 % n-pentane, 12 mole % isopentane, 8 mole %n-hexane, 30 mole %heptane and 10% nonane.
What are the product compositions and flow rates?

K1 (ethane) = 11.0
K2 (propane) = 4.6
K3 (n-butane) = 1.85
K4 (n-pentane) = 0.75
K5 (isopentane) = 0.9
K6 (n-hexane) = 0.32
K7 (heptane) = 0.14
K8 (nonane) = 0.026

x1 (ethane) = 0.033
x2 (propane) = 0.029
x3 (n-butane) = 0.128
x4 (n-pentane) = 0.123
x5 (isopentane) = 0.105
x6 (n-hexane) = 0.093
x7 (heptane) = 0.365
x8 (nonane) = 0.125

y1 (ethane) = 0.358
y2 (propane) = 0.132
y3 (n-butane) = 0.236
y4 (n-pentane) = 0.11
y5 (isopentane) = 0.079
y6 (n-hexane) = 0.03
y7 (heptane) = 0.051
y8 (nonane) = 0.003

V/F=0.207
V=207kg/hr
L=793kg/hr

V/F = View attachment 3132

Teach me how to calculate the vapour fraction...erm... i need you to show me one by one using the Newton Raphson method.

Sorry...i don't have any kind of programming here :laugh:
 
Gangster No.1 said:
just worked it out, took me 4 hours

= 37
Click to expand...

Sorry... the answers are wrong :-[

V/F=0.207
V=207kg/hr
L=793kg/hr

i also got it 37.

if only you can give me the summation series equation series...maybe i can check it again... I need in K1 K2 K3 K4 K5 K6 K7 K8 variable...i just don't know how to get rid of the Zi.

:enough!: (this is me...while calculating it)
 

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