maths
- Thread starter Tahmina
- Start date
- Replies 8
- Views 3K
British Wholesales - Certified Wholesale Linen & Towels | Halal Food Gastronomy | vBulletin 4 php 8.0 patch
is anyone gd at quadratics
i hav my summer exams next next
i need help on this question
Make X the subject of the formula y= 3x+4 divide by x-3
ta
I can try to help out if you could only clarify the question.
you mean as (x=) instead of (y=) then divide by (x-3) ?
I don't understand the last part, but here goes:
consider / as division, then:
y = 3x + 4
y - 4 = 3x + 4 - 4
(y - 4) / 3 = 3x / 3
(y - 4) / 3 = x
I hope that helped
I don't understand the last part, but here goes:
consider / as division, then:
y = 3x + 4
y - 4 = 3x + 4 - 4
(y - 4) / 3 = 3x / 3
(y - 4) / 3 = x
I hope that helped
~Raynn~
Esteemed Member
- Messages
- 205
- Reaction score
- 28
^ Okey dokey, in which case...
y = (3x + 4)/(x - 3)
(x - 3)y = 3x + 4 .....[multiply both sides by x - 3]
xy - 3y = 3x + 4 .....[expand the brackets]
xy - 3x = 3y + 4 .....[bring all the x terms on one side]
x (y - 3) = 3y + 4 .....[take out a factor of x]
x = (3y + 4)/(y - 3) .....[divide both sides by y - 3]
Hope that helps!
y = (3x + 4)/(x - 3)
(x - 3)y = 3x + 4 .....[multiply both sides by x - 3]
xy - 3y = 3x + 4 .....[expand the brackets]
xy - 3x = 3y + 4 .....[bring all the x terms on one side]
x (y - 3) = 3y + 4 .....[take out a factor of x]
x = (3y + 4)/(y - 3) .....[divide both sides by y - 3]
Hope that helps!
.