So there are 10 fishes in a tank..
- Thread starter Hulk
- Start date
- Replies 10
- Views 3K
British Wholesales - Certified Wholesale Linen & Towels | Halal Food Gastronomy | vBulletin 4 php 8.0 patch
marwen
IB Expert
- Messages
- 2,089
- Reaction score
- 596
- Gender
- Male
- Religion
- Islam
decrease ?
dead fish moves up over the surface. Part of the dead fish body will be out of the water, reducing the volume of water in the tank (volume of water = water + volume of fishes inside the water).
I need to make a real test to be sure this answer is correct (any idea how to kill a fish ?)
Lool ! good one.
dead fish moves up over the surface. Part of the dead fish body will be out of the water, reducing the volume of water in the tank (volume of water = water + volume of fishes inside the water).
I need to make a real test to be sure this answer is correct (any idea how to kill a fish ?)
Lool ! good one.
aadil77
Glory Be To Allah
- Messages
- 5,007
- Reaction score
- 978
- Gender
- Male
- Religion
- Islam
lol but it would make no difference to the water level
CosmicPathos
Anathema
- Messages
- 3,923
- Reaction score
- 530
- Gender
- Male
- Religion
- Islam
darn, a-levels physics, buyoancy and archimedes principles. darn I knew how to solve this!
Last edited:
CosmicPathos
Anathema
- Messages
- 3,923
- Reaction score
- 530
- Gender
- Male
- Religion
- Islam
ok guys here's the answer.
when the fish is alive, it is more dense than water, hence it sinks and stays beneath water surface. the volume of water it displaces would be equal to its volume.
now when the fish dies, it becomes less dense due to build up of gasses but its weight (assuming) will remain the same even though volume has increased (density = mass / volume). The volume of fluid displaced by this fish will always exert a greater force than the weight of the fish, and hence that is why it will float!!
now since the fish volume has increased, it will float. but now not all of the fish is floating. some of its body will be submerged, while the rest will be above the surface of water. The submerged volume of fish is what we are concerned with. This submerged volume of fish will displace an equal volume of water that is enough to exert upward force to keep the fish floating. Since this force is greater than the force exerted when the fish was fully submerged, we have to think which variable in the force changed. Force is given by Force = fluid density x gravity x volume of object
now since all the factors are same whether the fish is submerged or floating except volume of object or fish, in order for force to be greater for keeping the fish floating, the volume displaced by fish has to increase. Hence the water level will rise when the fish is floating, compared to when it was alive and deep down into the water.
feels good to answer this.
when the fish is alive, it is more dense than water, hence it sinks and stays beneath water surface. the volume of water it displaces would be equal to its volume.
now when the fish dies, it becomes less dense due to build up of gasses but its weight (assuming) will remain the same even though volume has increased (density = mass / volume). The volume of fluid displaced by this fish will always exert a greater force than the weight of the fish, and hence that is why it will float!!
now since the fish volume has increased, it will float. but now not all of the fish is floating. some of its body will be submerged, while the rest will be above the surface of water. The submerged volume of fish is what we are concerned with. This submerged volume of fish will displace an equal volume of water that is enough to exert upward force to keep the fish floating. Since this force is greater than the force exerted when the fish was fully submerged, we have to think which variable in the force changed. Force is given by Force = fluid density x gravity x volume of object
now since all the factors are same whether the fish is submerged or floating except volume of object or fish, in order for force to be greater for keeping the fish floating, the volume displaced by fish has to increase. Hence the water level will rise when the fish is floating, compared to when it was alive and deep down into the water.
feels good to answer this.
Last edited:
Scimitar
DAWAH DIGITAL
- Messages
- 7,549
- Reaction score
- 851
- Gender
- Male
- Religion
- Islam
ok guys here's the answer.
when the fish is alive, it is more dense than water, hence it sinks and stays beneath water surface. the volume of water it displaces would be equal to its volume.
now when the fish dies, it becomes less dense due to build up of gasses but its weight (assuming) will remain the same even though volume has increased (density = mass / volume). The volume of fluid displaced by this fish will always exert a greater force than the weight of the fish, and hence that is why it will float!!
now since the fish volume has increased, it will float. but now not all of the fish is floating. some of its body will be submerged, while the rest will be above the surface of water. The submerged volume of fish is what we are concerned with. This submerged volume of fish will displace an equal volume of water that is enough to exert upward force to keep the fish floating. Since this force is greater than the force exerted when the fish was fully submerged, we have to think which variable in the force changed. Force is given by Force = fluid density x gravity x volume of object
now since all the factors are same whether the fish is submerged or floating except volume of object or fish, in order for force to be greater for keeping the fish floating, the volume displaced by fish has to increase. Hence the water level will rise when the fish is floating, compared to when it was alive and deep down into the water.
feels good to answer this.
GEEEEK !!!
Scimi