a question.. who knows?

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Ill post the Q again unless it didnt show:

Two men are trapped inside four brick walls. All there is in the room includes a door that is locked from the outside and a bullet-proof window that is locked from the outside. The thing that locks the window is a stick that is movable if you apply great force. Finally, in the room is a fallen brick. After 15 minutes, the two men got out. How is this possible?
 
^ suggestion : get one hand out through the hole (where the brick is fallen), and move the stick that locks the window : the window opens and they get out.
 
marwen said:
^ suggestion : get one hand out through the hole (where the brick is fallen), and move the stick that locks the window : the window opens and they get out.
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Nope . . . .

Yaye :-\ Bro think of it like your own house lol, Logically, read every detail and apply it to yur own house, and compare the differences...

Read the Q, imagine ur one of those 2 men
 
^ suggestion2 : if there is no roof. then they can get out by climbing over the wall and jump out. the fallen brick may help in climbing the wall. and the can help each other (one climbs and one supports him).
 
marwen said:
^ suggestion2 : if there is no roof. then they can get out by climbing over the wall and jump out. the fallen brick may help in climbing the wall. and the can help each other (one climbs and one supports him).
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You are. . .


















































Correct:

The answer was:
They are trapped in a 4 WALL ROOM. If it had a ceiling and a floor it would be a 6-sided room. One man boosted the other over the wall and the man that got out went around and unlocked the door.
 
Well done, marwen!

The fallen brick was a red herring, eh??!
 
yeah lol

Ok, this is a riddle I found :
I fly, yet I have no wings. I cry, yet I have no eyes. Darkness follows me; lower light I never see.
What am I ?
 
мυѕℓιмαн 4 ℓιfє;1339989 said:
^Air? . . . . . . .or clouds?
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waaaw ! you must be very smart sis, it's clouds yes. You got it from the first try :°)
 
ok, this another question, but this one is about logic+maths :

We have 10 boxes. Every box contains 10 bricks of gold. Every brick is 1kg. So the weight of every box is 10kg.
But one of the 10 boxes is fake, i.e it contains non-gold bricks, each non-gold brick weighs 0.990 Kg (990g), i.e 10g less than a real gold brick.
We have a scale, but we must use it for just ONE weighing.
How can we know which is the fake gold box by using the scale just ONE time ?

If no one gives the answer, I'll give it tomorrow Incha'Allah :°)

assalamu 3alaykom.
 
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marwen said:
ok, this another question, but this one is about logic+maths :

We have 10 boxes. Every box contains 10 bricks of gold. Every brick is 1kg. So the weight of every box is 10kg.
But one of the 10 boxes is fake, i.e it contains non-gold bricks, each non-gold brick weighs 0.990 Kg (990g), i.e 10g less than a real gold brick.
We have a scale, but we must use it for just ONE weighing.
How can we know which is the fake gold box by using the scale just ONE time ?

If no one gives the answer, I'll give it tomorrow Incha'Allah :°)

assalamu 3alaykom.
Click to expand...

I don't know if this counts as 'one weighing' but here goes...

I will add the boxes one by one on the scale and keep reading...if the reading goes up by multiples of 10 its OK...the moment its shows something like xx.90...then the last box is the one.

But of course thats an over-simplified solution.
 
Imraan said:
I don't know if this counts as 'one weighing' but here goes...

I will add the boxes one by one on the scale and keep reading...if the reading goes up by multiples of 10 its OK...the moment its shows something like xx.90...then the last box is the one.

But of course thats an over-simplified solution.
Click to expand...

no sorry, that's not a single weighing operation. I want you to put something on the scale once and for all. and from just one reading you can conclude the answer. the trick is in the composition of the thing that you will weigh.
 
marwen said:
no sorry, that's not a single weighing operation. I want you to put something on the scale once and for all. and from just one reading you can conclude the answer. the trick is in the composition of the thing that you will weigh.
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Is this a single scale or a two-side scale (the one where you put weights on each side for comparison?)
 
^ you have to put the thing that you want to wigh in just one place. If it's tow-sided scale or not that doesn't matter.
 
Eww this 1 is a geeky 1, too geeky for me, no way i will get it , too much thinking to do :-\

Go nerds :D
 
c'mon guys, give a try ! before some guru in the forum give the answer lol.
Ok the answer is tricky but not very hard.
 
^ fake gold bricks are not different in appearance, so we have to detect them by weight.
 
^try moving/lifting the boxes with your bare hands first and whichever one is the lightest, is the box that contains the fake gold?
 

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