Basicallyyy...
- You know the mass of anhydrous BaSO4 (Mr = 233.1), obtained from the hydrated magnesium sulphate used at the start, 1.16g. Use this the find the number of mols of BaSO4 formed. (mols = mass/Mr; you get 0.004976...mols)
- This is also equal to the number of mols of hydrated crystals you started with...and, you're given the mass of the crystals, 1.23g. Use these values to find the Mr of the MgSO4.xH20 crystals. (Mr = mass/mols = 247.166...)
- The Mr of anhydrous MgSO4 is 120.4...subtract this from 247 to find the Mr of the xH20 part to get 126.76...
- Finally, divide this by the Mr of water, 18, to get x = 7.0
Man, this is a rather uncomfortable reminder of the coursework I'm still supposed to be doing...thus far, I have the title - "Determining the formula of Hydrated Copper Sulphate*: Evaluation".
Hold the applause.
*And this is after about 10 mins of debating whether or not to say 'copper sulphate crystals'