Mathematics Corner :)

Whatsthepoint said:
Nope. 3 is the only solution.
Click to expand...

I must be misinterpreting something or have totally forgot how to find prime numbers (Which is very probable)

Math never was one of my strong points.
 
56+28= 84

84 divide by 2(p) = 42

42 - 28 = 14
56 - 42 = 14

28 / 14 = 2
56 / 14 = 4

4 + 2 = 6

6 divide by 2(p) = 3

i think its soooo wrong lol
 
Woodrow said:
I must be misinterpreting something or have totally forgot how to find prime numbers (Which is very probable)

Math never was one of my strong points.
Click to expand...
p is prime
p + 28 is prime
p + 56 is prime
That's all there is to it.

I'll give it some more time.
 
inshallah i would ask brother wtp to give us daily equation to help boost our mathmatical knowledge
 
J.U.N.I.O.R said:
56+28= 84

84 divide by 2(p) = 42

42 - 28 = 14
56 - 42 = 14

28 / 14 = 2
56 / 14 = 4

4 + 2 = 6

6 divide by 2(p) = 3

i think its soooo wrong lol
Click to expand...
haha, you're very creative!:DBut basically what you did is this
28 = a
56 = 2a

a + 2a = 3a
3a/2 = 1.5a

1,5a - a = 0,5a
2a -1,5a = 0,5a

2a/0,5a = 4
a/0,5a = 2

4 + 2 = 6
6/2 = 3

so, it works with every a and 2a number.

the solution to this problem is simpler.
 
Assalamualaikum,

I am bad in maths while I'm in school, but this thread is good although I had left maths for more than three years. Last time I'm learning maths because I have to, now I can learn it for fun : ))))
 
I'll leave the prime thingy to potential solvers.
Here's an easier one, 8 grade math or something:

Ahmed, Mahmud, Muhammad, and Mehmet decided to buy a football. Ahmed contributed 40%, Mahmud payed 3/7 of what the other 3 gave, Muhammad gave 25% of what the other 3 gave and Mehmet payed 10 pounds.
How much did the bunch pay for the ball?
 
Whatsthepoint said:
p is prime
p + 28 is prime
p + 56 is prime
That's all there is to it.

I'll give it some more time.
Click to expand...

Every prime, other then 3, is 3k+1 or 3k-1.

If p=3k-1, then p + 28 = 3k + 27 = 3 (k + 9), this can't be a prime.

If p = 3k+1, then p + 56 = 3 (k+19), also not a prime.

So, the solution are the primes which are divisible by 3. The only solution is number 3. ;D
 
Abdu-l-Majeed said:
Every prime, other then 3, is 3k+1 or 3k-1.

If p=3k-1, then p + 28 = 3k + 27 = 3 (k + 9), this can't be a prime.

If p = 3k+1, then p + 56 = 3 (k+19), also not a prime.

So, the solution are the primes which are divisible by 3. The only solution is number 3. ;D
Click to expand...
Yep.
Are you a math student by chance?
 
Bismillahair Ramanhair Raheem
:sl:
Here is a real math question : How do you do area and perimeter? need very detailed version ( perhaps from zak:D). I'm asking because I failed this portion of math and have an upcoming exam about it. Jazakallah kayr.
:w:
 
All possible shapes pls.First simple ones such as square, triangle, trapezoid and rectangles first:).
 
what don't you understand yanal maybe i can help
you must think that math is easy that's first
then open the math's books
 

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