Nathaniel
Senior Member
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Ah, that's great!in the course notes it says 16π2 i think i made a mistake instead of (16.pi)^2 it should be 16.(pi^2)
i calculated Pt correcting the 16 pi squared issue and i got :
pt = 0.12 watts two d.p
and
pr = 0.10 watts to two d.p
which means my antenna has a loss of 0.02 which is absolutely sweet...the antenna looks effecient according to the calculations
cheers nathan for clearing things up!!!!!![]()

Glad it all worked out, I'm always happy to help.
